MATHS HELP!!!

[NM]

Bones A and B are x and y thousand years old respectively. Bone A contains 3 times as much carbon-14 as bone B.

State the relationship between the ages of bones A and B? Fully justify your answer.

 

[Tommy Napolitan]

um duhh this is easy? how can you not figure this out? this is 6th grade math

 

[Joe Riley]

If r = ratio of carbon-14 to carbon-12 then, if we take r = 1 in
living material (say branch of a tree) then with the half-life of 5730
years we have:

In 5730 years the value of r is down to 1/2

So we have the equation r = (1/2)^(t/5730) where t = time in years.

With this equation we can see that t = 0 gives r = 1

" t = 5730 gives r = 1/2

" t = 11460 gives r = 1/4

and so on.

So for bone A we have r(A) = (1/2)^(x/5730)

and for bone B we have r(B) = (1/2)^(y/5730)

and we are told r(A) = 3*r(B)

(1/2)^(x/5730) = 3*(1/2)^(y/3730)

(1/2)^(x/5730 - y/5730) = 3 and taking logs

(x-y)/5730 ln(1/2) = ln(3)

(x-y)/5730 = ln(3)/ln(1/2)

(x-y)/5730 = -1.584962

x - y = -9082

x = y - 9082

and so bone A is about 9000 years younger than bone B

im a genius.

 

[redline582]

A and B are next to each other in the alphabet.

 

[Tommy Napolitan]

If r = ratio of carbon-14 to carbon-12 then, if we take r = 1 in
living material (say branch of a tree) then with the half-life of 5730
years we have:

In 5730 years the value of r is down to 1/2

So we have the equation r = (1/2)^(t/5730) where t = time in years.

With this equation we can see that t = 0 gives r = 1

" t = 5730 gives r = 1/2

" t = 11460 gives r = 1/4

and so on.

So for bone A we have r(A) = (1/2)^(x/5730)

and for bone B we have r(B) = (1/2)^(y/5730)

and we are told r(A) = 3*r(B)

(1/2)^(x/5730) = 3*(1/2)^(y/3730)

(1/2)^(x/5730 - y/5730) = 3 and taking logs

(x-y)/5730 ln(1/2) = ln(3)

(x-y)/5730 = ln(3)/ln(1/2)

(x-y)/5730 = -1.584962

x - y = -9082

x = y - 9082

and so bone A is about 9000 years younger than bone B

im a genius.

This kid just won life. Please delete this site. I'm going to go commit suicide right now.

 

[Joe Riley]

If r = ratio of carbon-14 to carbon-12 then, if we take r = 1 in
living material (say branch of a tree) then with the half-life of 5730
years we have:

In 5730 years the value of r is down to 1/2

So we have the equation r = (1/2)^(t/5730) where t = time in years.

With this equation we can see that t = 0 gives r = 1

" t = 5730 gives r = 1/2

" t = 11460 gives r = 1/4

and so on.

So for bone A we have r(A) = (1/2)^(x/5730)

and for bone B we have r(B) = (1/2)^(y/5730)

and we are told r(A) = 3*r(B)

(1/2)^(x/5730) = 3*(1/2)^(y/3730)

(1/2)^(x/5730 - y/5730) = 3 and taking logs

(x-y)/5730 ln(1/2) = ln(3)

(x-y)/5730 = ln(3)/ln(1/2)

(x-y)/5730 = -1.584962

x - y = -9082

x = y - 9082

and so bone A is about 9000 years younger than bone B

im a genius.

This kid just won life. Please delete this site. I'm going to go commit suicide right now.

dude calm down i googled it

 

[Jordan Jasa]

If r = ratio of carbon-14 to carbon-12 then, if we take r = 1 in
living material (say branch of a tree) then with the half-life of 5730
years we have:

In 5730 years the value of r is down to 1/2

So we have the equation r = (1/2)^(t/5730) where t = time in years.

With this equation we can see that t = 0 gives r = 1

" t = 5730 gives r = 1/2

" t = 11460 gives r = 1/4

and so on.

So for bone A we have r(A) = (1/2)^(x/5730)

and for bone B we have r(B) = (1/2)^(y/5730)

and we are told r(A) = 3*r(B)

(1/2)^(x/5730) = 3*(1/2)^(y/3730)

(1/2)^(x/5730 - y/5730) = 3 and taking logs

(x-y)/5730 ln(1/2) = ln(3)

(x-y)/5730 = ln(3)/ln(1/2)

(x-y)/5730 = -1.584962

x - y = -9082

x = y - 9082

and so bone A is about 9000 years younger than bone B

im a genius.

This kid just won life. Please delete this site. I'm going to go commit suicide right now.

lol he's joe riley, he can't win at life.

but seriously joe, calm down with your posting please.

i might have been able to do that last year in alg 2, but geometry dumbed me down this year haha. too many spagetti bridges :/

 

[Tommy Napolitan]

If r = ratio of carbon-14 to carbon-12 then, if we take r = 1 in
living material (say branch of a tree) then with the half-life of 5730
years we have:

In 5730 years the value of r is down to 1/2

So we have the equation r = (1/2)^(t/5730) where t = time in years.

With this equation we can see that t = 0 gives r = 1

" t = 5730 gives r = 1/2

" t = 11460 gives r = 1/4

and so on.

So for bone A we have r(A) = (1/2)^(x/5730)

and for bone B we have r(B) = (1/2)^(y/5730)

and we are told r(A) = 3*r(B)

(1/2)^(x/5730) = 3*(1/2)^(y/3730)

(1/2)^(x/5730 - y/5730) = 3 and taking logs

(x-y)/5730 ln(1/2) = ln(3)

(x-y)/5730 = ln(3)/ln(1/2)

(x-y)/5730 = -1.584962

x - y = -9082

x = y - 9082

and so bone A is about 9000 years younger than bone B

im a genius.

This kid just won life. Please delete this site. I'm going to go commit suicide right now.

dude calm down i googled it

i wasnt serious haha i highly highly doubted you could understand that hahaha

 

[Joe Riley]

oh darn, i fail at life.

 

[Roycee]

Fuckk joe you have a lot of posts for 5 months !

 

[Joe Riley]

ive had pneumonia for the past 2 months and there are no video games at my house. this is pretty much all ive had to do.

 

[NM]

LOCK THREAD GOT THE ANSWER

 

[MattThomMakesMeWarmInside]

joe, your sucha postwhore, but I don't mind it at all. A friend of mine was telling me yeah man hes a post whore sooo many posts but then I said... you know joe is legit, he posts alot but I never really see a dumb post or you double posting or saying something completely inane... and yeah he agreed.

haha just thought id say that

 

[dre]

If r = ratio of carbon-14 to carbon-12 then, if we take r = 1 in
living material (say branch of a tree) then with the half-life of 5730
years we have:

In 5730 years the value of r is down to 1/2

So we have the equation r = (1/2)^(t/5730) where t = time in years.

With this equation we can see that t = 0 gives r = 1

" t = 5730 gives r = 1/2

" t = 11460 gives r = 1/4

and so on.

So for bone A we have r(A) = (1/2)^(x/5730)

and for bone B we have r(B) = (1/2)^(y/5730)

and we are told r(A) = 3*r(B)

(1/2)^(x/5730) = 3*(1/2)^(y/3730)

(1/2)^(x/5730 - y/5730) = 3 and taking logs

(x-y)/5730 ln(1/2) = ln(3)

(x-y)/5730 = ln(3)/ln(1/2)

(x-y)/5730 = -1.584962

x - y = -9082

x = y - 9082

and so bone A is about 9000 years younger than bone B

im a genius.

This kid just won life. Please delete this site. I'm going to go commit suicide right now.

dude calm down i googled it

i wasnt serious haha i highly highly doubted you could understand that hahaha

I understand it, but the original question is NOT that complicated, meaning Tommy's right, it is 6th grade math. The way I interpret it is if Bone A has 3 times as much C14 as bone B, then y = 3x. Could be wrong though..

 

[spitfire0453]

What the fuckkk is this, A talk about joe riley thread. Lmao

Wouldnt you die or something if you had phnemonia for that long?

 

[Big L]

What the fuckkk is this, A talk about joe riley thread. Lmao

Wouldnt you die or something if you had phnemonia for that long?

Hes not dead... what does that tell you